n列でprintfしますか？ [コピー]

殻に

$ n=30
$ dots=$(printf "%.0s." $(seq $n))
$ echo "$dots"
..............................

だから：

$ n=30
$ str='Add dots '
$ dots=$(printf "%.0s." $(seq $((n-${#str})) ))
$ echo "$str$dots"
Add dots .....................

そして：

$ n=30; str='Add dots dots '; dots=$(printf "%.0s." $(seq $((n-${#str})) )); echo "$str$dots"
Add dots dots ................

関数では：

$ dots(){ printf "%s" "$2"; printf "%.0s." $( seq $(($1-${#2})) );echo; }
$ dots 30 "Add dots dots dots "
Add dots dots dots ...........

$ dots 40 "Add dots dots dots "
Add dots dots dots .....................

$ dots 33 "we hold these truths "
we hold these truths ............