Todd Schneiderは彼の仕事で次のコマンドを使用しました。ニューヨーク市のタクシーデータ分析PostresSQL用のCSVファイルを準備します。
sed $'s/\r$//' $filename | sed '/^$/d' | ...
2 番目の sed コマンドは空行を削除します。最初は何をしますか?
答え1
によるとman bash
:
Words of the form $'string' are treated specially. The word expands to string, with backslash-escaped characters replaced as specified by the ANSI C standard. Backslash escape sequences, if present, are decoded as follows: \a alert (bell) \b backspace \e \E an escape character \f form feed \n new line \r carriage return \t horizontal tab \v vertical tab \\ backslash \' single quote \" double quote \? question mark \nnn the eight-bit character whose value is the octal value nnn (one to three digits) \xHH the eight-bit character whose value is the hexadecimal value HH (one or two hex digits) \uHHHH the Unicode (ISO/IEC 10646) character whose value is the hexadecimal value HHHH (one to four hex digits) \UHHHHHHHH the Unicode (ISO/IEC 10646) character whose value is the hexadecimal value HHHHHHHH (one to eight hex digits) \cx a control-x character The expanded result is single-quoted, as if the dollar sign had not been present.
したがって、$'s/\r$//'
行の末尾からASCIIを削除してください。CR
これは、Windows行終端をUNIX行終端に変換する粗い方法です。