ディレクトリ内のファイル(バイナリファイルを除く)の文字列(位置パス)を再帰的に置き換える方法は?私はコマンドを試しました
find . -type f -exec sed -i 's/foo/bar/g' {} +
ただし、バイナリファイルやその他のファイル(* .o、* .c)の文字列も置き換えられます。 「.dependent」という名前のすべてのファイルで文字列を再帰的に変更したいと思います。
答え1
find . -type f -name "*.depend" -exec sed -i 's/foo/bar/g' {} +
または
find . -type f -not -name "*.c" -not -name "*.o" -exec sed -i 's/foo/bar/g' {} +
-name pattern
Base of file name (the path with the leading directories
removed) matches shell pattern pattern. Because the leading
directories are removed, the file names considered for a match
with -name will never include a slash, so `-name a/b' will
never match anything (you probably need to use -path instead).
A warning is issued if you try to do this, unless the
environment variable POSIXLY_CORRECT is set. The
metacharacters (`*', `?', and `[]') match a `.' at the start
of the base name (this is a change in findutils-4.2.2; see
section STANDARDS CONFORMANCE below). To ignore a directory
and the files under it, use -prune; see an example in the
description of -path. Braces are not recognised as being
special, despite the fact that some shells including Bash
imbue braces with a special meaning in shell patterns. The
filename matching is performed with the use of the fnmatch(3)
library function. Don't forget to enclose the pattern in
quotes in order to protect it from expansion by the shell.
答え2
私はこのコードを書いており、それは私の目的に適しています。
find . -type f -exec grep -Iq . {} \; -exec sed -i 's|/foo|/bar|g' {} +