複数フォルダのファイルの違いを確認する

Question

シェルループの場合、これは考える必要もないように聞こえます。これはzsh、bash、dashで動作します...

cd .snapshot
original="weekly.2024-04-14_0015/my/path/to/the/file.php"
pathonly="$(echo "${original}" | sed 's;^[^/]*/\(.*\)$;\1;')" # cut off head directory

orig_hash=$(sha1sum "${original}" | sed 's/^\([^ ]*\) .*$/\1/')

for candidate in */"${pathonly}" ; do
  # don't compare file to itself, that'd be silly
  [[ "${candidate}" = "${original}" ]] && continue 

  cand_hash=$(sha1sum "${candidate}" | sed 's/^\([^ ]*\) .*$/\1/')

  # check hashes, so that we don't have to read the original N times
  ( [[ "${orig_hash}" = "${cand_hash}" ]] && \
  # if the hashes match, use the cmp tool to compare files byte by byte
    cmp -- "${candidate}" "${original}" ) || \
    # if either the hash equality or the content equality fail, print file name
    printf '%s differs\n' "${candidate}"
done

Answer 1

シェルループの場合、これは考える必要もないように聞こえます。これはzsh、bash、dashで動作します...

cd .snapshot
original="weekly.2024-04-14_0015/my/path/to/the/file.php"
pathonly="$(echo "${original}" | sed 's;^[^/]*/\(.*\)$;\1;')" # cut off head directory

orig_hash=$(sha1sum "${original}" | sed 's/^\([^ ]*\) .*$/\1/')

for candidate in */"${pathonly}" ; do
  # don't compare file to itself, that'd be silly
  [[ "${candidate}" = "${original}" ]] && continue 

  cand_hash=$(sha1sum "${candidate}" | sed 's/^\([^ ]*\) .*$/\1/')

  # check hashes, so that we don't have to read the original N times
  ( [[ "${orig_hash}" = "${cand_hash}" ]] && \
  # if the hashes match, use the cmp tool to compare files byte by byte
    cmp -- "${candidate}" "${original}" ) || \
    # if either the hash equality or the content equality fail, print file name
    printf '%s differs\n' "${candidate}"
done

複数フォルダのファイルの違いを確認する

答え1

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